#include<iostream>
using namespace std;
int main(){  // C++ 14级 13位ISBN号码的校验码
	//978-7-121-4 1 4 8 9 - 3
	//012345678910111213141516
	int n1,n2,n3,n4,n5,n6,n7,n8,n9,n10,n11,n12,n13,sum=0;
	string s;
	cin>>s;
	n1=s[0]-'0';
	n2=s[1]-'0';
	n3=s[2]-'0';
	n4=s[4]-'0';
	n5=s[6]-'0';
	n6=s[7]-'0';
	n7=s[8]-'0';
	n8=s[10]-'0';
	n9=s[11]-'0';
	n10=s[12]-'0';
	n11=s[13]-'0';
	n12=s[14]-'0';
	sum=(n1+n3+n5+n7+n9+n11+(n2+n4+n6+n8+n10+n12)*3)%10;
	if(sum==0) n13=0;
	else n13=10-sum;
	//cout<<"sum:"<<sum<<" n13:"<<n13<<endl;
	if(n13==s[16]-'0') cout<<"yes";
	else cout<<"no";
	return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main(){ // 13位ISBN号码的校验码
	string s,s2="";
	cin>>s; //全部输入 
	long long sum=0;
	for(int i=0;i<s.length();i++)
		if(s[i]>='0' and s[i]<='9')
			s2+=s[i]; //把数字提取出来，横线去掉 
	for(int i=0;i<s2.length()-1;i++){ //除过最后一位，前边的交替乘1和3做累加 
		if(i%2==0){
			sum+=(s2[i]-'0');
		}else{
			sum+=(s2[i]-'0')*3;
		}
	}
	sum%=10; //累加完取余数 
	if(sum!=0) //余数不等于0的话再用10减去这个余数 
		sum=10-sum;
	if(sum==s2[s2.length()-1]-'0') //判断结果是否和最后一位相等 
		cout<<"yes";
	else
		cout<<"no";
		
	return 0;
}